Uri.HostNameType Свойство

public:
 property UriHostNameType HostNameType { UriHostNameType get(); };

public UriHostNameType HostNameType { get; }

member this.HostNameType : UriHostNameType

Public ReadOnly Property HostNameType As UriHostNameType

UriHostNameType

Элемент перечисления UriHostNameType.

В следующем примере создается Uri экземпляр и записывается в HostNameType консоль.

Uri^ address1 = gcnew Uri( "http://www.contoso.com/index.htm#search" );
Console::WriteLine( "address 1 {0} a valid scheme name",
   Uri::CheckSchemeName( address1->Scheme ) ? (String^)" has" : " does not have" );
if ( address1->Scheme == Uri::UriSchemeHttp )
{
   Console::WriteLine( "Uri is HTTP type" );
}

Console::WriteLine( address1->HostNameType );

Uri address1 = new Uri("http://www.contoso.com/index.htm#search");
Console.WriteLine("address 1 {0} a valid scheme name",
      Uri.CheckSchemeName(address1.Scheme) ? " has" : " does not have");

if (address1.Scheme == Uri.UriSchemeHttp)
    Console.WriteLine("Uri is HTTP type");

Console.WriteLine(address1.HostNameType);

let address1 = Uri "http://www.contoso.com/index.htm#search"
printfn $"""address 1 {if Uri.CheckSchemeName address1.Scheme then " has" else " does not have"} a valid scheme name"""

if address1.Scheme = Uri.UriSchemeHttp then
    printfn "Uri is HTTP type"

printfn $"{address1.HostNameType}"

Dim address1 As New Uri("http://www.contoso.com/index.htm#search")
Console.WriteLine("address 1 {0} a valid scheme name", IIf(Uri.CheckSchemeName(address1.Scheme), " has", " does not have")) 'TODO: For performance reasons this should be changed to nested IF statements

If address1.Scheme = Uri.UriSchemeHttp Then
    Console.WriteLine("Uri is HTTP type")
End If 
Console.WriteLine(address1.HostNameType)