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Sign inSqlInt16.Modulus(SqlInt16, SqlInt16) Method
Definition
Important
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Divides two SqlInt16 values and returns the remainder.
public:
static System::Data::SqlTypes::SqlInt16 Modulus(System::Data::SqlTypes::SqlInt16 x, System::Data::SqlTypes::SqlInt16 y);C#
public static System.Data.SqlTypes.SqlInt16 Modulus(System.Data.SqlTypes.SqlInt16 x, System.Data.SqlTypes.SqlInt16 y);static member Modulus : System.Data.SqlTypes.SqlInt16 * System.Data.SqlTypes.SqlInt16 -> System.Data.SqlTypes.SqlInt16Public Shared Function Modulus (x As SqlInt16, y As SqlInt16) As SqlInt16The remainder left after division is performed on x and y.
If either instance of x or y is null, the value is null.
Applies to
| Product | Versions |
|---|---|
| .NET | Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9, 10 |
| .NET Framework | 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1 |
| .NET Standard | 2.0, 2.1 |