DataSet.GetXmlSchema Method

public:
 System::String ^ GetXmlSchema();

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("Members from serialized types may use dynamic code generation.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("Members from serialized types may be trimmed if not referenced directly.")]
public string GetXmlSchema();

public string GetXmlSchema();

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("Members from serialized types may be trimmed if not referenced directly.")]
public string GetXmlSchema();

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("Members from serialized types may use dynamic code generation.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("Members from serialized types may be trimmed if not referenced directly.")>]
member this.GetXmlSchema : unit -> string

member this.GetXmlSchema : unit -> string

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("Members from serialized types may be trimmed if not referenced directly.")>]
member this.GetXmlSchema : unit -> string

Public Function GetXmlSchema () As String

Returns

String that is the XML Schema for the XML representation of the data stored in the DataSet.

Attributes

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Examples

The following example creates a DataSet and DataTable, and then displays the schema in XML format.

private static void DemonstrateGetXml()
{
    // Create a DataSet with one table containing
    // two columns and 10 rows.
    DataSet dataSet = new DataSet("dataSet");
    DataTable table = dataSet.Tables.Add("Items");
    table.Columns.Add("id", typeof(int));
    table.Columns.Add("Item", typeof(string));

    // Add ten rows.
    DataRow row;
    for(int i = 0; i <10;i++)
    {
        row = table.NewRow();
        row["id"]= i;
        row["Item"]= "Item" + i;
        table.Rows.Add(row);
    }

    // Display the DataSet contents as XML.
    Console.WriteLine( dataSet.GetXml() );
}

Private Shared Sub DemonstrateGetXml()
    ' Create a DataSet with one table 
    ' containing two columns and 10 rows.
    Dim dataSet As New DataSet("dataSet")
    Dim table As DataTable = dataSet.Tables.Add("Items")
    table.Columns.Add("id", Type.GetType("System.Int32"))
    table.Columns.Add("Item", Type.GetType("System.String"))

    ' Add ten rows.
    Dim row As DataRow
    Dim i As Integer
    For i = 0 To 9
        row = table.NewRow()
        row("id") = i
        row("Item")= "Item" & i
        table.Rows.Add(row)
    Next

    ' Display the DataSet contents as XML.
    Console.WriteLine( dataSet.GetXml() )
End Sub

Remarks

Calling this method is identical to calling WriteXmlSchema, except that only the primary schema is written.

GetXmlSchema returns XML as a string, and therefore requires more overhead than WriteXmlSchema to write XML to a file.

If you build a DataSet using schema inference and serialize it using XML or Web services, the column ordering may change.

See also

• Using DataSets in ADO.NET