JsonSerializer.Deserialize Метод

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

public:
 static System::Object ^ Deserialize(System::IO::Stream ^ utf8Json, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);

public static object? Deserialize(System.IO.Stream utf8Json, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);

static member Deserialize : System.IO.Stream * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> obj

Public Function Deserialize (utf8Json As Stream, jsonTypeInfo As JsonTypeInfo) As Object

Параметры

Возвращаемое значение

Представление jsonTypeInfo значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

public:
 static System::Object ^ Deserialize(System::Text::Json::Utf8JsonReader % reader, Type ^ returnType, System::Text::Json::Serialization::JsonSerializerContext ^ context);

public static object? Deserialize(ref System.Text.Json.Utf8JsonReader reader, Type returnType, System.Text.Json.Serialization.JsonSerializerContext context);

static member Deserialize : Utf8JsonReader * Type * System.Text.Json.Serialization.JsonSerializerContext -> obj

Public Function Deserialize (ByRef reader As Utf8JsonReader, returnType As Type, context As JsonSerializerContext) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Исключения

Комментарии

TokenType Если свойство reader имеет PropertyName или None, средство чтения будет расширено одним вызовом, чтобы Read() определить начало значения.

После завершения этого метода reader размещается в последнем маркере в значении JSON. Если возникает исключение, средство чтения сбрасывается в состояние, в которое он находился при вызове метода.

Этот метод делает копию данных, с помощью чего средство чтения действовало, поэтому не требуется вызывающий объект для поддержания целостности данных за пределами возврата этого метода.

Используется JsonReaderOptions для создания экземпляра приоритета Utf8JsonReader над JsonSerializerOptions конфликтом. Следовательно, AllowTrailingCommasи MaxDepthCommentHandling используются во время чтения.

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(ref System.Text.Json.Utf8JsonReader reader, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object? Deserialize(ref System.Text.Json.Utf8JsonReader reader, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(ref System.Text.Json.Utf8JsonReader reader, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object Deserialize(ref System.Text.Json.Utf8JsonReader reader, Type returnType, System.Text.Json.JsonSerializerOptions options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : Utf8JsonReader * Type * System.Text.Json.JsonSerializerOptions -> obj

static member Deserialize : Utf8JsonReader * Type * System.Text.Json.JsonSerializerOptions -> obj

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : Utf8JsonReader * Type * System.Text.Json.JsonSerializerOptions -> obj

Public Function Deserialize (ByRef reader As Utf8JsonReader, returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Public Shared Function Deserialize (ByRef reader As Utf8JsonReader, returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Комментарии

TokenType Если свойство reader имеет JsonTokenType.PropertyName или JsonTokenType.None, средство чтения будет расширено одним вызовом, чтобы Utf8JsonReader.Read() определить начало значения.

После завершения этого метода reader будет размещаться в последнем токене в значении JSON. Если возникает исключение, средство чтения сбрасывается в состояние, в которое он находился при вызове метода.

Этот метод делает копию данных, с помощью чего средство чтения действовало, поэтому не требуется вызывающий объект для поддержания целостности данных за пределами возврата этого метода.

Используется JsonReaderOptions для создания экземпляра приоритета Utf8JsonReader над JsonSerializerOptions конфликтом. Следовательно, JsonReaderOptions.AllowTrailingCommasи JsonReaderOptions.MaxDepthJsonReaderOptions.CommentHandling используются во время чтения.

Дополнительные сведения см. в статье "Сериализация и десериализация JSON".

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

public:
[System::Runtime::CompilerServices::Extension]
 static System::Object ^ Deserialize(System::Text::Json::Nodes::JsonNode ^ node, Type ^ returnType, System::Text::Json::Serialization::JsonSerializerContext ^ context);

public static object? Deserialize(this System.Text.Json.Nodes.JsonNode? node, Type returnType, System.Text.Json.Serialization.JsonSerializerContext context);

static member Deserialize : System.Text.Json.Nodes.JsonNode * Type * System.Text.Json.Serialization.JsonSerializerContext -> obj

<Extension()>
Public Function Deserialize (node As JsonNode, returnType As Type, context As JsonSerializerContext) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(this System.Text.Json.Nodes.JsonNode? node, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(this System.Text.Json.Nodes.JsonNode? node, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object? Deserialize(this System.Text.Json.Nodes.JsonNode? node, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.Nodes.JsonNode * Type * System.Text.Json.JsonSerializerOptions -> obj

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.Nodes.JsonNode * Type * System.Text.Json.JsonSerializerOptions -> obj

static member Deserialize : System.Text.Json.Nodes.JsonNode * Type * System.Text.Json.JsonSerializerOptions -> obj

<Extension()>
Public Function Deserialize (node As JsonNode, returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

public:
[System::Runtime::CompilerServices::Extension]
 static System::Object ^ Deserialize(System::Text::Json::JsonElement element, Type ^ returnType, System::Text::Json::Serialization::JsonSerializerContext ^ context);

public static object? Deserialize(this System.Text.Json.JsonElement element, Type returnType, System.Text.Json.Serialization.JsonSerializerContext context);

static member Deserialize : System.Text.Json.JsonElement * Type * System.Text.Json.Serialization.JsonSerializerContext -> obj

<Extension()>
Public Function Deserialize (element As JsonElement, returnType As Type, context As JsonSerializerContext) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(this System.Text.Json.JsonElement element, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(this System.Text.Json.JsonElement element, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object? Deserialize(this System.Text.Json.JsonElement element, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.JsonElement * Type * System.Text.Json.JsonSerializerOptions -> obj

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.JsonElement * Type * System.Text.Json.JsonSerializerOptions -> obj

static member Deserialize : System.Text.Json.JsonElement * Type * System.Text.Json.JsonSerializerOptions -> obj

<Extension()>
Public Function Deserialize (element As JsonElement, returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

public:
[System::Runtime::CompilerServices::Extension]
 static System::Object ^ Deserialize(System::Text::Json::JsonDocument ^ document, Type ^ returnType, System::Text::Json::Serialization::JsonSerializerContext ^ context);

public static object? Deserialize(this System.Text.Json.JsonDocument document, Type returnType, System.Text.Json.Serialization.JsonSerializerContext context);

static member Deserialize : System.Text.Json.JsonDocument * Type * System.Text.Json.Serialization.JsonSerializerContext -> obj

<Extension()>
Public Function Deserialize (document As JsonDocument, returnType As Type, context As JsonSerializerContext) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(this System.Text.Json.JsonDocument document, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(this System.Text.Json.JsonDocument document, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object? Deserialize(this System.Text.Json.JsonDocument document, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.JsonDocument * Type * System.Text.Json.JsonSerializerOptions -> obj

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.JsonDocument * Type * System.Text.Json.JsonSerializerOptions -> obj

static member Deserialize : System.Text.Json.JsonDocument * Type * System.Text.Json.JsonSerializerOptions -> obj

<Extension()>
Public Function Deserialize (document As JsonDocument, returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(string json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object? Deserialize(string json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(string json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object Deserialize(string json, Type returnType, System.Text.Json.JsonSerializerOptions options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : string * Type * System.Text.Json.JsonSerializerOptions -> obj

static member Deserialize : string * Type * System.Text.Json.JsonSerializerOptions -> obj

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : string * Type * System.Text.Json.JsonSerializerOptions -> obj

Public Function Deserialize (json As String, returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Public Shared Function Deserialize (json As String, returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Комментарии

Использование не String так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Дополнительные сведения см. в статье "Сериализация и десериализация JSON".

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

public:
 static System::Object ^ Deserialize(ReadOnlySpan<char> json, Type ^ returnType, System::Text::Json::Serialization::JsonSerializerContext ^ context);

public static object? Deserialize(ReadOnlySpan<char> json, Type returnType, System.Text.Json.Serialization.JsonSerializerContext context);

static member Deserialize : ReadOnlySpan<char> * Type * System.Text.Json.Serialization.JsonSerializerContext -> obj

Public Function Deserialize (json As ReadOnlySpan(Of Char), returnType As Type, context As JsonSerializerContext) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Исключения

Комментарии

Использование не String так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(ReadOnlySpan<char> json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(ReadOnlySpan<char> json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object? Deserialize(ReadOnlySpan<char> json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : ReadOnlySpan<char> * Type * System.Text.Json.JsonSerializerOptions -> obj

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : ReadOnlySpan<char> * Type * System.Text.Json.JsonSerializerOptions -> obj

static member Deserialize : ReadOnlySpan<char> * Type * System.Text.Json.JsonSerializerOptions -> obj

Public Function Deserialize (json As ReadOnlySpan(Of Char), returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Комментарии

Использование диапазона UTF-16 не так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

public:
 static System::Object ^ Deserialize(System::String ^ json, Type ^ returnType, System::Text::Json::Serialization::JsonSerializerContext ^ context);

public static object? Deserialize(string json, Type returnType, System.Text.Json.Serialization.JsonSerializerContext context);

static member Deserialize : string * Type * System.Text.Json.Serialization.JsonSerializerContext -> obj

Public Function Deserialize (json As String, returnType As Type, context As JsonSerializerContext) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Исключения

Комментарии

Использование не String так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(ReadOnlySpan<byte> utf8Json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object? Deserialize(ReadOnlySpan<byte> utf8Json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(ReadOnlySpan<byte> utf8Json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object Deserialize(ReadOnlySpan<byte> utf8Json, Type returnType, System.Text.Json.JsonSerializerOptions options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : ReadOnlySpan<byte> * Type * System.Text.Json.JsonSerializerOptions -> obj

static member Deserialize : ReadOnlySpan<byte> * Type * System.Text.Json.JsonSerializerOptions -> obj

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : ReadOnlySpan<byte> * Type * System.Text.Json.JsonSerializerOptions -> obj

Public Function Deserialize (utf8Json As ReadOnlySpan(Of Byte), returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Public Shared Function Deserialize (utf8Json As ReadOnlySpan(Of Byte), returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Комментарии

Дополнительные сведения см. в статье "Сериализация и десериализация JSON".

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

public:
 static System::Object ^ Deserialize(ReadOnlySpan<System::Byte> utf8Json, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);

public static object? Deserialize(ReadOnlySpan<byte> utf8Json, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);

static member Deserialize : ReadOnlySpan<byte> * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> obj

Public Function Deserialize (utf8Json As ReadOnlySpan(Of Byte), jsonTypeInfo As JsonTypeInfo) As Object

Параметры

Возвращаемое значение

Представление jsonTypeInfo значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

public:
 static System::Object ^ Deserialize(ReadOnlySpan<System::Byte> utf8Json, Type ^ returnType, System::Text::Json::Serialization::JsonSerializerContext ^ context);

public static object? Deserialize(ReadOnlySpan<byte> utf8Json, Type returnType, System.Text.Json.Serialization.JsonSerializerContext context);

static member Deserialize : ReadOnlySpan<byte> * Type * System.Text.Json.Serialization.JsonSerializerContext -> obj

Public Function Deserialize (utf8Json As ReadOnlySpan(Of Byte), returnType As Type, context As JsonSerializerContext) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

public:
 static System::Object ^ Deserialize(System::String ^ json, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);

public static object? Deserialize(string json, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);

static member Deserialize : string * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> obj

Public Function Deserialize (json As String, jsonTypeInfo As JsonTypeInfo) As Object

Параметры

Возвращаемое значение

Представление jsonTypeInfo значения JSON.

Исключения

Комментарии

Использование не String так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

public:
[System::Runtime::CompilerServices::Extension]
 static System::Object ^ Deserialize(System::Text::Json::JsonDocument ^ document, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);

public static object? Deserialize(this System.Text.Json.JsonDocument document, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);

static member Deserialize : System.Text.Json.JsonDocument * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> obj

<Extension()>
Public Function Deserialize (document As JsonDocument, jsonTypeInfo As JsonTypeInfo) As Object

Параметры

Возвращаемое значение

Представление jsonTypeInfo значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

public:
[System::Runtime::CompilerServices::Extension]
 static System::Object ^ Deserialize(System::Text::Json::JsonElement element, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);

public static object? Deserialize(this System.Text.Json.JsonElement element, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);

static member Deserialize : System.Text.Json.JsonElement * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> obj

<Extension()>
Public Function Deserialize (element As JsonElement, jsonTypeInfo As JsonTypeInfo) As Object

Параметры

Возвращаемое значение

Представление jsonTypeInfo значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

public:
 static System::Object ^ Deserialize(ReadOnlySpan<char> json, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);

public static object? Deserialize(ReadOnlySpan<char> json, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);

static member Deserialize : ReadOnlySpan<char> * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> obj

Public Function Deserialize (json As ReadOnlySpan(Of Char), jsonTypeInfo As JsonTypeInfo) As Object

Параметры

Возвращаемое значение

Представление jsonTypeInfo значения JSON.

Исключения

Комментарии

Использование не String так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

public:
 static System::Object ^ Deserialize(System::Text::Json::Utf8JsonReader % reader, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);

public static object? Deserialize(ref System.Text.Json.Utf8JsonReader reader, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);

static member Deserialize : Utf8JsonReader * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> obj

Public Function Deserialize (ByRef reader As Utf8JsonReader, jsonTypeInfo As JsonTypeInfo) As Object

Параметры

Возвращаемое значение

Представление jsonTypeInfo значения JSON.

Исключения

Комментарии

TokenType Если свойство reader имеет PropertyName или None, средство чтения будет расширено одним вызовом, чтобы Read() определить начало значения.

После завершения этого метода reader будет размещаться в последнем токене в значении JSON. Если возникает исключение, средство чтения сбрасывается в состояние, в которое он находился при вызове метода.

Этот метод делает копию данных, с помощью чего средство чтения действовало, поэтому не требуется вызывающий объект для поддержания целостности данных за пределами возврата этого метода.

Используется JsonReaderOptions для создания экземпляра приоритета Utf8JsonReader над JsonSerializerOptions конфликтом. Следовательно, AllowTrailingCommasи MaxDepthCommentHandling используются во время чтения.

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(System.IO.Stream utf8Json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static object? Deserialize(System.IO.Stream utf8Json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

public static object? Deserialize(System.IO.Stream utf8Json, Type returnType, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.IO.Stream * Type * System.Text.Json.JsonSerializerOptions -> obj

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.IO.Stream * Type * System.Text.Json.JsonSerializerOptions -> obj

static member Deserialize : System.IO.Stream * Type * System.Text.Json.JsonSerializerOptions -> obj

Public Function Deserialize (utf8Json As Stream, returnType As Type, Optional options As JsonSerializerOptions = Nothing) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

public:
 static System::Object ^ Deserialize(System::IO::Stream ^ utf8Json, Type ^ returnType, System::Text::Json::Serialization::JsonSerializerContext ^ context);

public static object? Deserialize(System.IO.Stream utf8Json, Type returnType, System.Text.Json.Serialization.JsonSerializerContext context);

static member Deserialize : System.IO.Stream * Type * System.Text.Json.Serialization.JsonSerializerContext -> obj

Public Function Deserialize (utf8Json As Stream, returnType As Type, context As JsonSerializerContext) As Object

Параметры

Возвращаемое значение

Представление returnType значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

public:
[System::Runtime::CompilerServices::Extension]
 static System::Object ^ Deserialize(System::Text::Json::Nodes::JsonNode ^ node, System::Text::Json::Serialization::Metadata::JsonTypeInfo ^ jsonTypeInfo);

public static object? Deserialize(this System.Text.Json.Nodes.JsonNode? node, System.Text.Json.Serialization.Metadata.JsonTypeInfo jsonTypeInfo);

static member Deserialize : System.Text.Json.Nodes.JsonNode * System.Text.Json.Serialization.Metadata.JsonTypeInfo -> obj

<Extension()>
Public Function Deserialize (node As JsonNode, jsonTypeInfo As JsonTypeInfo) As Object

Параметры

Возвращаемое значение

Представление jsonTypeInfo значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

public:
generic <typename TValue>
[System::Runtime::CompilerServices::Extension]
 static TValue Deserialize(System::Text::Json::JsonDocument ^ document, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);

public static TValue? Deserialize<TValue>(this System.Text.Json.JsonDocument document, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);

static member Deserialize : System.Text.Json.JsonDocument * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> 'Value

<Extension()>
Public Function Deserialize(Of TValue) (document As JsonDocument, jsonTypeInfo As JsonTypeInfo(Of TValue)) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

public:
generic <typename TValue>
 static TValue Deserialize(System::Text::Json::Utf8JsonReader % reader, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);

public static TValue? Deserialize<TValue>(ref System.Text.Json.Utf8JsonReader reader, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);

static member Deserialize : Utf8JsonReader * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> 'Value

Public Function Deserialize(Of TValue) (ByRef reader As Utf8JsonReader, jsonTypeInfo As JsonTypeInfo(Of TValue)) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Исключения

Комментарии

TokenType Если свойство reader имеет PropertyName или None, средство чтения будет расширено одним вызовом, чтобы Read() определить начало значения.

После завершения этого метода reader размещается в последнем маркере в значении JSON. Если возникает исключение, средство чтения сбрасывается в состояние, в которое он находился при вызове метода.

Этот метод делает копию данных, с помощью чего средство чтения действовало, поэтому не требуется вызывающий объект для поддержания целостности данных за пределами возврата этого метода.

Используется JsonReaderOptions для создания экземпляра приоритета Utf8JsonReader над JsonSerializerOptions конфликтом. Следовательно, AllowTrailingCommasи MaxDepthCommentHandling используются во время чтения.

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

Исходный код:

JsonSerializer.Read.Utf8JsonReader.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(ref System.Text.Json.Utf8JsonReader reader, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue? Deserialize<TValue>(ref System.Text.Json.Utf8JsonReader reader, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(ref System.Text.Json.Utf8JsonReader reader, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue Deserialize<TValue>(ref System.Text.Json.Utf8JsonReader reader, System.Text.Json.JsonSerializerOptions options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : Utf8JsonReader * System.Text.Json.JsonSerializerOptions -> 'Value

static member Deserialize : Utf8JsonReader * System.Text.Json.JsonSerializerOptions -> 'Value

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : Utf8JsonReader * System.Text.Json.JsonSerializerOptions -> 'Value

Public Function Deserialize(Of TValue) (ByRef reader As Utf8JsonReader, Optional options As JsonSerializerOptions = Nothing) As TValue

Public Shared Function Deserialize(Of TValue) (ByRef reader As Utf8JsonReader, Optional options As JsonSerializerOptions = Nothing) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Комментарии

TokenType Если свойство reader имеет JsonTokenType.PropertyName или JsonTokenType.None, средство чтения будет расширено одним вызовом, чтобы Utf8JsonReader.Read() определить начало значения.

После завершения этого метода reader будет размещаться в последнем токене в значении JSON. Если возникает исключение, средство чтения сбрасывается в состояние, в которое он находился при вызове метода.

Этот метод делает копию данных, с помощью чего средство чтения действовало, поэтому не требуется вызывающий объект для поддержания целостности данных за пределами возврата этого метода.

Используется JsonReaderOptions для создания экземпляра приоритета Utf8JsonReader над JsonSerializerOptions конфликтом. Следовательно, JsonReaderOptions.AllowTrailingCommasи JsonReaderOptions.MaxDepthJsonReaderOptions.CommentHandling используются во время чтения.

Дополнительные сведения см. в статье "Сериализация и десериализация JSON".

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

public:
generic <typename TValue>
[System::Runtime::CompilerServices::Extension]
 static TValue Deserialize(System::Text::Json::Nodes::JsonNode ^ node, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);

public static TValue? Deserialize<TValue>(this System.Text.Json.Nodes.JsonNode? node, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);

static member Deserialize : System.Text.Json.Nodes.JsonNode * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> 'Value

<Extension()>
Public Function Deserialize(Of TValue) (node As JsonNode, jsonTypeInfo As JsonTypeInfo(Of TValue)) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

Исходный код:

JsonSerializer.Read.Node.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(this System.Text.Json.Nodes.JsonNode? node, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(this System.Text.Json.Nodes.JsonNode? node, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue? Deserialize<TValue>(this System.Text.Json.Nodes.JsonNode? node, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.Nodes.JsonNode * System.Text.Json.JsonSerializerOptions -> 'Value

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.Nodes.JsonNode * System.Text.Json.JsonSerializerOptions -> 'Value

static member Deserialize : System.Text.Json.Nodes.JsonNode * System.Text.Json.JsonSerializerOptions -> 'Value

<Extension()>
Public Function Deserialize(Of TValue) (node As JsonNode, Optional options As JsonSerializerOptions = Nothing) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

public:
generic <typename TValue>
[System::Runtime::CompilerServices::Extension]
 static TValue Deserialize(System::Text::Json::JsonElement element, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);

public static TValue? Deserialize<TValue>(this System.Text.Json.JsonElement element, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);

static member Deserialize : System.Text.Json.JsonElement * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> 'Value

<Extension()>
Public Function Deserialize(Of TValue) (element As JsonElement, jsonTypeInfo As JsonTypeInfo(Of TValue)) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

Исходный код:

JsonSerializer.Read.Element.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(this System.Text.Json.JsonElement element, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(this System.Text.Json.JsonElement element, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue? Deserialize<TValue>(this System.Text.Json.JsonElement element, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.JsonElement * System.Text.Json.JsonSerializerOptions -> 'Value

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.JsonElement * System.Text.Json.JsonSerializerOptions -> 'Value

static member Deserialize : System.Text.Json.JsonElement * System.Text.Json.JsonSerializerOptions -> 'Value

<Extension()>
Public Function Deserialize(Of TValue) (element As JsonElement, Optional options As JsonSerializerOptions = Nothing) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

Исходный код:

JsonSerializer.Read.Document.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(this System.Text.Json.JsonDocument document, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(this System.Text.Json.JsonDocument document, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue? Deserialize<TValue>(this System.Text.Json.JsonDocument document, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.JsonDocument * System.Text.Json.JsonSerializerOptions -> 'Value

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.Text.Json.JsonDocument * System.Text.Json.JsonSerializerOptions -> 'Value

static member Deserialize : System.Text.Json.JsonDocument * System.Text.Json.JsonSerializerOptions -> 'Value

<Extension()>
Public Function Deserialize(Of TValue) (document As JsonDocument, Optional options As JsonSerializerOptions = Nothing) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(ReadOnlySpan<byte> utf8Json, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue? Deserialize<TValue>(ReadOnlySpan<byte> utf8Json, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(ReadOnlySpan<byte> utf8Json, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue Deserialize<TValue>(ReadOnlySpan<byte> utf8Json, System.Text.Json.JsonSerializerOptions options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : ReadOnlySpan<byte> * System.Text.Json.JsonSerializerOptions -> 'Value

static member Deserialize : ReadOnlySpan<byte> * System.Text.Json.JsonSerializerOptions -> 'Value

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : ReadOnlySpan<byte> * System.Text.Json.JsonSerializerOptions -> 'Value

Public Function Deserialize(Of TValue) (utf8Json As ReadOnlySpan(Of Byte), Optional options As JsonSerializerOptions = Nothing) As TValue

Public Shared Function Deserialize(Of TValue) (utf8Json As ReadOnlySpan(Of Byte), Optional options As JsonSerializerOptions = Nothing) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Комментарии

Дополнительные сведения см. в статье "Сериализация и десериализация JSON".

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(string json, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue? Deserialize<TValue>(string json, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(string json, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue Deserialize<TValue>(string json, System.Text.Json.JsonSerializerOptions options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : string * System.Text.Json.JsonSerializerOptions -> 'Value

static member Deserialize : string * System.Text.Json.JsonSerializerOptions -> 'Value

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : string * System.Text.Json.JsonSerializerOptions -> 'Value

Public Function Deserialize(Of TValue) (json As String, Optional options As JsonSerializerOptions = Nothing) As TValue

Public Shared Function Deserialize(Of TValue) (json As String, Optional options As JsonSerializerOptions = Nothing) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Комментарии

Использование не String так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Дополнительные сведения см. в статье "Сериализация и десериализация JSON".

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

public:
generic <typename TValue>
 static TValue Deserialize(ReadOnlySpan<char> json, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);

public static TValue? Deserialize<TValue>(ReadOnlySpan<char> json, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);

static member Deserialize : ReadOnlySpan<char> * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> 'Value

Public Function Deserialize(Of TValue) (json As ReadOnlySpan(Of Char), jsonTypeInfo As JsonTypeInfo(Of TValue)) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Исключения

Комментарии

Использование не String так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(ReadOnlySpan<char> json, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(ReadOnlySpan<char> json, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue? Deserialize<TValue>(ReadOnlySpan<char> json, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : ReadOnlySpan<char> * System.Text.Json.JsonSerializerOptions -> 'Value

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : ReadOnlySpan<char> * System.Text.Json.JsonSerializerOptions -> 'Value

static member Deserialize : ReadOnlySpan<char> * System.Text.Json.JsonSerializerOptions -> 'Value

Public Function Deserialize(Of TValue) (json As ReadOnlySpan(Of Char), Optional options As JsonSerializerOptions = Nothing) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Комментарии

Использование диапазона UTF-16 не так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

Исходный код:

JsonSerializer.Read.Span.cs

public:
generic <typename TValue>
 static TValue Deserialize(ReadOnlySpan<System::Byte> utf8Json, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);

public static TValue? Deserialize<TValue>(ReadOnlySpan<byte> utf8Json, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);

static member Deserialize : ReadOnlySpan<byte> * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> 'Value

Public Function Deserialize(Of TValue) (utf8Json As ReadOnlySpan(Of Byte), jsonTypeInfo As JsonTypeInfo(Of TValue)) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

public:
generic <typename TValue>
 static TValue Deserialize(System::IO::Stream ^ utf8Json, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);

public static TValue? Deserialize<TValue>(System.IO.Stream utf8Json, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);

static member Deserialize : System.IO.Stream * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> 'Value

Public Function Deserialize(Of TValue) (utf8Json As Stream, jsonTypeInfo As JsonTypeInfo(Of TValue)) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Исключения

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

Исходный код:

JsonSerializer.Read.Stream.cs

[System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")]
[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(System.IO.Stream utf8Json, System.Text.Json.JsonSerializerOptions? options = default);

[System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")]
public static TValue? Deserialize<TValue>(System.IO.Stream utf8Json, System.Text.Json.JsonSerializerOptions? options = default);

public static TValue? Deserialize<TValue>(System.IO.Stream utf8Json, System.Text.Json.JsonSerializerOptions? options = default);

[<System.Diagnostics.CodeAnalysis.RequiresDynamicCode("JSON serialization and deserialization might require types that cannot be statically analyzed and might need runtime code generation. Use System.Text.Json source generation for native AOT applications.")>]
[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.IO.Stream * System.Text.Json.JsonSerializerOptions -> 'Value

[<System.Diagnostics.CodeAnalysis.RequiresUnreferencedCode("JSON serialization and deserialization might require types that cannot be statically analyzed. Use the overload that takes a JsonTypeInfo or JsonSerializerContext, or make sure all of the required types are preserved.")>]
static member Deserialize : System.IO.Stream * System.Text.Json.JsonSerializerOptions -> 'Value

static member Deserialize : System.IO.Stream * System.Text.Json.JsonSerializerOptions -> 'Value

Public Function Deserialize(Of TValue) (utf8Json As Stream, Optional options As JsonSerializerOptions = Nothing) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Атрибуты

RequiresDynamicCodeAttribute RequiresUnreferencedCodeAttribute

Исключения

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

Исходный код:

JsonSerializer.Read.String.cs

public:
generic <typename TValue>
 static TValue Deserialize(System::String ^ json, System::Text::Json::Serialization::Metadata::JsonTypeInfo<TValue> ^ jsonTypeInfo);

public static TValue? Deserialize<TValue>(string json, System.Text.Json.Serialization.Metadata.JsonTypeInfo<TValue> jsonTypeInfo);

static member Deserialize : string * System.Text.Json.Serialization.Metadata.JsonTypeInfo<'Value> -> 'Value

Public Function Deserialize(Of TValue) (json As String, jsonTypeInfo As JsonTypeInfo(Of TValue)) As TValue

Параметры типа

Параметры

Возвращаемое значение

Представление TValue значения JSON.

Исключения

Комментарии

Использование не String так эффективно, как использование методов UTF-8, так как реализация изначально использует UTF-8.