AsyncEnumerable.Sequence<T>(T, T, T) Method
Definition
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Generates a sequence that begins with start and yields additional values each incremented by step until endInclusive is reached.
public:
generic <typename T>
where T : System::Numerics::INumber<T> static System::Collections::Generic::IAsyncEnumerable<T> ^ Sequence(T start, T endInclusive, T step);public static System.Collections.Generic.IAsyncEnumerable<T> Sequence<T>(T start, T endInclusive, T step) where T : System.Numerics.INumber<T>;static member Sequence : 'T * 'T * 'T -> System.Collections.Generic.IAsyncEnumerable<'T (requires 'T :> System.Numerics.INumber<'T>)> (requires 'T :> System.Numerics.INumber<'T>)Public Function Sequence(Of T As INumber(Of T)) (start As T, endInclusive As T, step As T) As IAsyncEnumerable(Of T)Type Parameters
- T
The type of the value to be yielded in the result sequence.
Parameters
- start
- T
The starting value. This value will always be included in the resulting sequence.
- endInclusive
- T
The ending bound beyond which values will not be included in the sequence.
- step
- T
The amount by which the next value in the sequence should be incremented from the previous value.
Returns
An IAsyncEnumerable<T> that contains the sequence.
Exceptions
endInclusive is null.
step is zero and endInclusive does not equal start.
