MyInvocation.MyCommand problems

Question

_{Friday, October 26, 2012 9:11 AM}

If I write a script Test1.ps which has following 2 lines

$dir = split-path -parent $MyInvocation.MyCommand.Definition

echo $dir

it works fine. but I change it to

function GetPath() {

    $f = split-path -parent $MyInvolcation.MyCommand.Definition

    $f

}

$dir = GetPath

Write-Host $dir

it gets me a blank.

Very Annoying!!!!

val it: unit=()

All replies (5)

_{Sunday, October 28, 2012 12:07 AM ✅Answered | 3 votes}

If you use PowerShell V3 you can use the variable $PSScriptRoot to get the path of the script.

-Raimund

_{Friday, October 26, 2012 9:42 AM}

[cmdletbinding()]
Param()
function GetPath() {
 [cmdletbinding()]
 Param()
    $MyInvocation.MyCommand.Definition
}
getpath
$MyInvocation.MyCommand.Definition

Notice that definition value is changing when in function

if You need path use

$MyInvocation.MyCommand.Path

_{Friday, October 26, 2012 6:16 PM}

I don't understand this code why do yo u have repeated cmdletbindign() and param()? what is their purpose?

val it: unit=()

_{Friday, October 26, 2012 10:04 PM | 1 vote}

I don't understand this code why do yo u have repeated cmdletbindign() and param()? what is their purpose?

val it: unit=()

the first set will apply to the script in which they are contained, the second to the function in which they are contained. A bit redundant perhaps, and not necessary for the purpose. But if run from a .ps1 file it illustrates that the value of "$MyInvocation.MyCommand.Definition" is dependent on where it is invoked from.

Al Dunbar -- remember to 'mark or propose as answer' or 'vote as helpful' as appropriate.

_{Monday, October 29, 2012 7:24 AM}

Hi,

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