Event Procedures for Right-Click popup menu

Question

_{Thursday, June 7, 2018 3:59 PM}

I found the following code but do not know how to add event function, something like OnClick() that will run when clicking on menu items. Please advise. Thanks.

$form1= New-Object System.Windows.Forms.Form
$textBox1 = New-Object System.Windows.Forms.TextBox
$contextMenuStrip1 = New-Object System.Windows.Forms.ContextMenuStrip

$contextMenuStrip1.Items.Add("Item 1")
$contextMenuStrip1.Items.Add("Item 2")

$textBox1.ShortcutsEnabled = $false
$textBox1.ContextMenuStrip = $contextMenuStrip1

$form1.Text="Context Menu for TextBox"
$form1.Controls.Add($textBox1)

$form1.ShowDialog()

All replies (3)

_{Thursday, June 7, 2018 4:21 PM ✅Answered}

Not sure if you can have this for text boxes, you might have to use focus on that instead of add click.

$objectname.add_click({ #code in here to run when clicked })

Hope this helps.

_{Thursday, June 7, 2018 4:52 PM ✅Answered}

$menu1 = $contextMenuStrip1.Items.Add("Item 1")

$menu1 = $contextMenuStrip1.Items.Add("Item 1")
$menu1.add_Click({Write-Host $this.Text})
$menu2 = $contextMenuStrip1.Items.Add("Item 2")
$menu2.add_Click({Write-Host $this.Text})

\(ツ)_/

_{Thursday, June 7, 2018 4:46 PM}

Thanks for your answer.

I added in $contextMenuStrip1.Add_click({ Write-Host 'Clicked Item 1' })
and it works when clicking on 'Item 1' or 'Item 2' 

How to detect which item clicked in the click event?

$form1= New-Object System.Windows.Forms.Form
$textBox1 = New-Object System.Windows.Forms.TextBox
$contextMenuStrip1 = New-Object System.Windows.Forms.ContextMenuStrip
$contextMenuStrip1.Items.Add("Item 1")
$contextMenuStrip1.Items.Add("Item 2")
$contextMenuStrip1.Add_click({ Write-Host 'Clicked Item 1' })

$textBox1.ShortcutsEnabled = $false
$textBox1.ContextMenuStrip = $contextMenuStrip1
$form1.Text="Context Menu for TextBox"
$form1.Controls.Add($textBox1)
$form1.ShowDialog()