TreeView Node Selection based on Fullpath

Article
2013-01-23

Question

_{Wednesday, January 23, 2013 10:32 AM}

Hello ,

I am working on Windows form and I have 2 Treeview controls. If I select a Node in TreeView1 then Same Node in TreeView2 should be selected(if present).

So here is how I have written a code.

tvPD1 is first Treeview and tvPD2 is second TreeView Control.

        private void tvPD1_AfterSelect(object sender, TreeViewEventArgs e)
        {
            string leftTVFullPath = e.Node.FullPath;
       
            GetNodeFromPath(tvPD2.Nodes, leftTVFullPath);
        }
 
        public TreeNode GetNodeFromPath(TreeNodeCollection nodes, string path)
        {
            TreeNode foundNode = null;
            foreach (TreeNode tn in nodes)
            {
                if (tn.FullPath == path)
                {
                    tvPD2.SelectedNode = tn;
                    tvPD2.SelectedNode.EnsureVisible();  
                    tvPD2.Focus();
                    return tn;
                }
                else if (tn.Nodes.Count > 0)
                {
                    foundNode = GetNodeFromPath(tn.Nodes, path);
                }
                if (foundNode != null)
                    return foundNode;
            }
            return null;
        }

The main Problem with the above code is ..If there are two or more elements with the same name at the same level in the tree, this will return the first of the elements. How can we implement such function ?

Regards

Vyasa

All replies (5)

_{Thursday, January 24, 2013 6:00 AM ✅Answered}

FarnhamSurrey

this may be useful to you...atleast you will get some idea.....

http://stackoverflow.com/questions/12234729/treeview-how-to-expand-a-fullpath-c-sharp

_{Thursday, January 24, 2013 11:04 AM ✅Answered}

Before you add new Node, check for duplicate names and if needed set new Node.Name to something unique - now you can use Find method to find correct Node.

i.e.

// example: new node name
string TreeNodeText = "newNode";

string TreeNodeName = TreeNodeText;
int nameIndex = 0;

while (Treeview1.Nodes.Find(TreeNodeName, true).Length > 0 || Treeview2.Nodes.Find(TreeNodeName, true).Length > 0)
{
    TreeNodeName = TreeNodeText + nameIndex.ToString();
    nameIndex++;
}
// now you can add new Node to Treeview1, Treeview2 or both...
TreeNode newNode = Treeview2.Nodes.Add(TreeNodeText);// ...but with different identifier.
newNode.Name = TreeNodeName;

To find corresponding Node:

TreeNode selNode = Treeview1.SelectedNode;
TreeNode[] muchingNodes = Treeview2.Nodes.Find(selNode.Name, true);// ...add i.e. select...
if (muchingNodes.Length > 0)
    Treeview2.SelectedNode = muchingNodes[0];

_{Wednesday, January 23, 2013 10:38 AM}

If I understand you correctly, you are saying you could have a treeview like this:

a
b
c
b
d

With two nodes at the second level called "b". Let me know if my understanding is incorrect, but if I am right, I suppose you could try using the Index property of TreeNode rather than FullPath. If it is not a business requirement to have duplicate names for nodes, you couilid also require the nodes to have unique names, thereby avoiding this issue

_{Thursday, January 24, 2013 4:41 AM}

Ya, your understanding is correct but the thing is the order of 2 treeviews is not same. So there i will have problem again.

eg:

Treeview1 TreeView2

a                           a
b                            b
    c                             e
b                            b
    d                             c
b                            b
    e                             d

In these case how can I select the node ?

_{Thursday, January 24, 2013 8:25 AM}

Using Index to identify the node could still work for you here

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TreeView Node Selection based on Fullpath

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